Beginning Python: Using Python 2.6 and Python 3.1ISBN: 978-0-470-41463-7
Paperback
624 pages
February 2010
This is a Print-on-Demand title. It will be printed specifically to fill your order. Please allow an additional 10-15 days delivery time. The book is not returnable.
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Do you think you've discovered an error in this book? Please check the list of errata below to see if we've already addressed the error. If not, please submit the error via our Errata Form. We will attempt to verify your error; if you're right, we will post a correction below.
Chapter | Page | Details | Date | Print Run |
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6 | Error in Code Current syntax: raise TypeError, "add_one requires a string, given a %s" % type (food_name) Correct syntax: raise TypeError( "add_one requires a string, given a %s" % type (food_name) ) |
05/28/2010 | ||
11 | Error in Text In the Try It Out section, under the 2nd code example (under header ?You could also just skip??): "John" "Everyman" should be: 'JohnEveryman' not: JohnEveryman |
05/02/2011 | ||
12 | Error in Code In the code under ?Joining Strings with the Print() Function? The ?p? in Print(?John??) function should be lower case? print(?John??). |
05/02/2011 | ||
14 | Error in Text Exercise in ch 1 N0 1 says to type, "rock a by...." It should say ?print? in front of ?rock?? |
10/20/2010 | ||
23 | Error in Code Under?some surprises? heading: Update for Python 3.1.3 windows installation: For >>>4023 - 22.4 Answer should be: 4000.6 not: 4000.5999999999999 |
05/02/2011 | ||
27 | Error in Text "It may seem like a mistake that the second number printed is 12 when you ? ve provided the string with a 10. However, octal only has 8 numbers (0 to 7), so from 0 to 10 in octal is 0, 1, 2, 3, 4, 5, 6, 7, 8, 10, 11." When using the octal counting system you do not actually count the '8' aswell. So one should count as followed: 0, 1, 2, 3, 4, 5, 6, 7, 10, 11, 12 |
08/27/2010 | ||
40 | Error in Code There is a typo in the code. menu_specials.value() should be: menu_specials.values() |
07/15/2010 |